Chemistry 30

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Chemical Kinetics

Answers to Practice Questions: Calculating Reaction Rates

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1.

In the following decomposition reaction,

 2 N2O5 → 4 NO2 + O2

oxygen gas is produced at the average rate of 9.1 × 10-4 mol · L-1 · s-1. Over the same period, what is the average rate of the following:

  • the production of nitrogen dioxide
  • the loss of nitrogen pentoxide
 

Solution:

  • From the equation we see that for every 1 mole of oxygen formed, four moles of nitrogen dioxide are produced. Thus, the rate of production of nitrogen dioxide is four times that of oxygen:
rate NO2 production = 4 × (9.1 × 10-4 mol · L-1· s-1)
  = 3.6 × 10-3 mol · L-1· s-1
  • Nitrogen pentoxide is consumed at twice the rate that oxygen is produced:
rate loss of N2O5 = 2× (9.1 × 10-4 mol · L-1· s-1)
  = 1.8 × 10-3 mol · L-1· s-1

 

 
2.

Consider the following reaction:

N2(g) + 3 H2(g) → 2 NH3(g)

If the rate of loss of hydrogen gas is 0.03 mol · L-1· s-1, what is the rate of production of ammonia?

 

Solution:

From the balanced equation we see that there are 2 moles NH3 produced for every 3 moles H2 used. Thus:

rate NH3 production
=
2

3
× (0.03 mol · L-1· s-1)
  = 0.02 mol · L-1· s-1

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Credits | Central iSchool | Sask Learning | Saskatchewan Evergreen Curriculum | Updated: 26-Jun-2006