Chemistry 30

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Redox Reactions & Electrochemistry Practice Answers

Practice Set 5: Predicting Reactions and Electrolytic Cells

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  1. Using either an activity series (Table 11.2) or Table of Standard Reduction Potentials, predict whether a reaction takes place, and if so, give a balanced reaction equation.

    a. Ag(s) + HCl(aq)

    Answer:

     Using Activity Series we determine no reaction will occur since Ag is lower on the list than H.

     Using Standard Reduction Potentials:

    Write out half-reactions in a way that will produce the equation in question (that is with solid Ag and aqueous H+ ions as reactants (Cl- will be a spectator ion). Remember to reverse the sign of E° if you reverse an equation:

Ag(s) → Ag+ + e-

-0.80

2H+ + 2e- → H2

0.00

Net Voltage

-0.80

Conclusion – since the voltage (E°) is negative, the reaction WILL NOT BE spontaneous. No reaction will occur.


 b. Mg(s) + FeSO4(aq)

Answer:

 Using Activity Series we find that a reaction will occur because Mg is higher on the list than Fe.

Using Standard Reduction Potentials:

SO42- will be a spectator ion.

 

Mg(s) → Mg2+ + 2e-

+2.37

Fe2+ + 2e- →Fe

-0.45

Net Voltage

+1.92

Conclusion – since a positive voltage results, the reaction WILL BE spontaneous.

The balanced equation for the reaction will be:

Mg(s) + FeSO4(s) → MgSO4(aq) + Fe(s)


c. Cu(s) + AuCl3(aq)

Answer:

Using Activity Series we find that a reaction will occur because Cu is higher on the list than Au

Using Standard Reduction Potentials:

Cl- will be a spectator ion.

 

Cu(s) → Cu2+ + 2e-

-0.34

Au3+ + 3e- → Au

+1.50

Net Voltage

+1.1

Conclusion – since a positive voltage results, the reaction WILL BE spontaneous.

The balanced equation for the reaction will be:

3 Cu(s) + AuCl3(aq) → 3 CuCl2 (aq) + 2 Au(s)


d. Sn(s)+ Al2(SO4)3(s)

Answer:

Using Activity Series - no reaction. Sn is lower on the list than Al

Using Standard Reduction Potentials:

SO42- will be a spectator ion.

 

Sn(s) → Sn2+ + 2e-

+0.14

Al3+ + 3e- → Al

-1.66

Net Voltage

-1.52

Conclusion – since the voltage is negative, this reaction WILL NOT BE spontaneous.


2. Consider the electrolysis of water. Describe the events at the anode in terms of

a. the reaction

Oxidation always occurs at the anode. Thus the anode reaction is

2 H2O(l) → O2 (g) + 4 H+(aq) + 4 e-

b. pH H+ is being produced. As [H+] increases, pH decreases (the solution becomes more acidic)
c. gas produced

O2 gas is produced at the anode

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Credits | Central iSchool | Sask Learning | Saskatchewan Evergreen Curriculum | Updated: 22-May-2006